Try the Free Math Solver or Scroll down to Tutorials!

 Depdendent Variable

 Number of equations to solve: 23456789
 Equ. #1:
 Equ. #2:

 Equ. #3:

 Equ. #4:

 Equ. #5:

 Equ. #6:

 Equ. #7:

 Equ. #8:

 Equ. #9:

 Solve for:

 Dependent Variable

 Number of inequalities to solve: 23456789
 Ineq. #1:
 Ineq. #2:

 Ineq. #3:

 Ineq. #4:

 Ineq. #5:

 Ineq. #6:

 Ineq. #7:

 Ineq. #8:

 Ineq. #9:

 Solve for:

 Please use this form if you would like to have this math solver on your website, free of charge. Name: Email: Your Website: Msg:

Adding or Subtracting Rational Expressions with Different Denominators

Here is the procedure for adding (or subtracting) fractions.

Procedure

To Add or Subtract Rational Expressions That Have Different Denominators

Step 1 Find the LCD.

Step 2 Rewrite each rational expression with the LCD as the denominator.

Step 3 Add or subtract the numerators. The denominator stays the same.

Step 4 Reduce to lowest terms.

Example

 Solution Step 1 Find the LCD. Factor each denominator. The LCD is (5x + 2)(x - 1)(x + 6) Step 2 Rewrite each rational expression using the LCD. Multiply the first fraction by and the second by Simplify the numberators Step 3 Add. Combine like terms
 Step 4 Reduce. The numerator cannot be factored. This rational expression is in lowest terms. We will leave the denominator in factored form. So, the result is .

Note:

To factor 5x2 - 3x - 2:

â€¢ Find two integers whose product is 5(-2) = -10, and whose sum is -3. They are 2 and -5.

â€¢ Use these integers to rewrite 5x2 - 3x - 2 as 5x2 + 2x - 5x - 2.

â€¢ Factor by grouping. x(5x + 2) - 1(5x + 2) = (5x + 2)(x + 1)

To factor x2 + 5x - 6:

â€¢ Find two integers whose product is -6 and whose sum is 5. They are -1 and 6.

â€¢ Use these integers to write the factorization (x - 1)(x + 6).